[Cbor] Re: EDN -0

[Joe Hildebrand <[e-mail]>]

Eh, I don't care that much, -0 => 0 is fine with me.  I think this way is more likely to be surprising than -0 -> -0.0, but the simple rule is alluring.

Can we document it?

— 
Joe Hildebrand

> On Aug 26, 2024, at 8:13 PM, Rohan Mahy <[e-mail]> wrote:
> 
> > Why would I have typed -0 if I wanted 0? 
> Let's be clear. The user typed something dumb. If they wanted floating point -0.0 they should have written that. If they wanted 0, they should have typed that. We are debating if it is better to make an exception to the simple rule about having a decimal point or other indicator of floating point present to make something floating point or not. Every other integer is represented as a CBOR integer. 
> 
> > It *doesn't* have a value in the integer space, like NaN or Infinity.
> In the integer space -0 *equals* 0.  -0 does not have a *unique* value in the integer space, but it *does* have a value.
> 
> Thanks,
> -rohan
> 
> On Mon, Aug 26, 2024 at 6:17 PM Joe Hildebrand <[e-mail]> wrote:
> Why would I have typed -0 if I wanted 0? 
> 
> It *doesn't* have a value in the integer space, like NaN or Infinity.
> 
> — 
> Joe Hildebrand
> 
> > On Aug 26, 2024, at 5:35 PM, Rohan Mahy <[e-mail]> wrote:
> > 
> > Why not represent EDN -0 be the unsigned int zero since it has the value in the integer space and has no decimal point?
> > Thanks,
> > -r
> > 
> > 
> > On Mon, Aug 26, 2024 at 3:56 PM Joe Hildebrand <[e-mail]> wrote:
> > Perhaps EDN -0 is supposed to be denote the integer 0 because of this language:
> > 
> > 
> > ```
> > decnumber stands for an integer in the usual decimal notation, unless at least one of the optional parts starting with "." and "e" are present, in which case it stands for a floating point value in the usual decimal notation. Note that the grammar now allows 3. for 3.0 and .3 for 0.3 (also for hexadecimal floating point below); implementers are advised that some platform numeric parsers accept only a subset of the floating point syntax in this document and may require some preprocessing to use here.
> > ```
> > 
> > I implemented -0 to always return a float, since it's the only number without a decimal or exponent that can't be encoded as an integer.  I think that's more correct, but I am willing to be wrong.
> > 
> > Either way, can we have an explicit call out for -0 in this paragraph?
> > 
> > — 
> > Joe Hildebrand
> > 
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