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[CFRG] Combinitorics probabilities

Robert Moskowitz <rgm-sec@htt-consult.com> Mon, 08 August 2022 20:58 UTC

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Subject: [CFRG] Combinitorics probabilities
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Well I spent the afternoon googling, but my search foo is weak.

I want the formula for the probablity of receiving at least m out of n 
messages given the probablity of receiving any message is p.

I did find:

https://www.statology.org/probability-of-at-least-two/#:~:text=P(X%E2%89%A52)%20%3D,(X%E2%89%A52)%20%3D%200.3673

But this is a series to find the final answer, not the 'final' formula.

So for example to receive at least 2 out of 3 messages where the 
probablity of any message at 95% comes out to 97.2%

But what about 3 out of 5?  etc.

Pointer is greatly appreciated.

I took stat just too many decades ago, and I have not kept that knife sharp.

thanks

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