Re: [v6ops] A proposal for draft-ietf-6man-rfc4291bis-07 - FE80:: means FE80::/9

Alexandre Petrescu <alexandre.petrescu@gmail.com> Tue, 07 March 2017 21:19 UTC

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Subject: Re: [v6ops] A proposal for draft-ietf-6man-rfc4291bis-07 - FE80:: means FE80::/9
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From: Alexandre Petrescu <alexandre.petrescu@gmail.com>
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Date: Tue, 7 Mar 2017 22:19:21 +0100
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Thanks to this discussion, I would like to promote the following fact 
that I did not know:

If you say "FE80::" without telling the prefix length, that actually 
means "FE80::/9" (and not FE80::/10, nor FE80::/64).  Because 0xFE80  is 
"1111 1110 1000 0000" in binary representation.

Alex


Le 07/03/2017 à 19:49, Alexandre Petrescu a écrit :
>
>
> Le 07/03/2017 à 17:38, Sander Steffann a écrit :
>> Hi,
>>
>>>> In step 3 the N rightmost bits of that are overwritten with the
>>>> N-bits-long IID.
>>>
>>> YEs, that covers the 64bit rightmost part.  But that does not say
>>> what to put between /10 and /64.
>>
>> Yes it does. In whatever way you read it those bits contain 0.
>
> Here it goes: FE80:1::1 does not contain 0s.
>
> Nothing can stop me from putting a 1 there.
>
> The RFCs should get corrected.
>
>> I'm going to stop this thread, this discussion is going nowhere...
>> You seem to have made up your mind that you *want* to interpret the
>> RFCs in a way that doesn't make sense, and it's not my job to fix
>> that...
>
> "prefix FE80::0" is incorrect please remove that from that RFC.  Say
> "prefix FE80::/10" instead.
>
> Alex
>
>>
>> Cheers, Sander
>>
>
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