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You make a very valid point.   Segmented Feb 25 at 15:49
4
@caveman The fact that nothing grants fgets permission to change any bytes other than those explicitly specified to be modified means that such an implementation of fgets would fail to conform. In the abstract machine, fgets does not change those bytes, and the value of those bytes does not become indeterminate, unspecified or undefined. Therefore, concrete implementations must maintain the behaviour of leaving those bytes at their last-stored values. If you disagree, then what do you think about the example in my answer? Is that allowed to print "1\n2\n"? If not, why not?   hvd Feb 25 at 19:43
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That's a good argument, and I agree. I think your comment makes a clearer argument than your answer itself. The main point that I was missing from your answer is that you are considering each byte an object. So the statement that they don't become indeterminate, unspecified, or defined really clarifies what you are saying.   caveman Feb 25 at 20:01
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This probably not all there is to it as far the standard goes. What defines the last-stored value can be a long story, or else you wouldn't be able to have memory-mapped registers that can be changed by the hardware (which is a common technique on many embedded platforms).   Respawned Fluff Feb 25 at 22:12
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@RespawnedFluff The standard attaches a footnote to that saying "In the case of a volatile object, the last store need not be explicit in the program.". And that footnote is backed up by the normative text describingvolatile (6.7.3p6). But in the OP's case, there are no volatile objects, so that isn't an issue.   hvd Feb 26 at 6:38


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