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which book is this?   Shikhar Bhardwaj Feb 2 at 11:46

The book is: amazon.co.uk/Tour-C--Depth/dp/0321958314/   Andy Res Feb 2 at 11:48
2
Just to expand on these nice answers, you're confusing null pointers (what you're looping is actually checking for) and null terminators (what you want to check for, the character that terminates a C string).  nanny Feb 2 at 14:56

Thank you for pointing it out.   Andy Res Feb 2 at 15:01

I suggest you throw that book in the recycle bin, and curse all 'programmers' who suggest you write cutsie code like that. If you write the code so that the intended meaning is clear - "while (p != NULL)" it's pretty obvious that you're stepping the pointer p through all memory. Instead you want "while (*p != '\0')", checking for a null-terminated string


Your code (while(p)) loops as long as p isn't zero. P is the pointer to the array, and you keep incrementing it and check memory past the array's bounds. That's the cause of the segmentation fault.
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answered Feb 2 at 11:38
zmbq
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up vote2down vote

to my surprise it does not stop there, but it continues to cycle, which I suppose might be the cause of segmentation fault?

This happens because you are checking the pointer for NULL, rather than checking what it points to for '\0':
while(*p){