Re: [magma] Question about IGMPv3 state change

Hi Kunal,

             X is for all INCLUDE mode sources. A is TO_IN report. So, s5
should be there in X. Why should s5 be blocked? Somebody wants data from
this source.

Thanks,
Indranil

On Mon, Mar 7, 2011 at 5:52 PM, Kunal Shah <kunal.shah@ericsson.com> wrote:

>  Hi Indranil,
>
> Consider this,
>
> X= s1,s2
> Y= s3,s4
>
> A=s4,s5
>
> Then X+A= s1,s2,s4,s5
> Y-A=s3
>
> s5 is in X even when it is not being blocked ??
>
> Kunal
>
>  ------------------------------
> *From:* Indranil Bhattacharya [mailto:myselfindranil@gmail.com]
> *Sent:* Monday, February 28, 2011 6:57 PM
> *To:* Kunal Shah
> *Cc:* magma@ietf.org
> *Subject:* Re: [magma] Question about IGMPv3 state change
>
>   Hi Kunal,
>
>
> x = s1,s2
> y= s3,s4
> a=s2,s3
>
> x+a = s1,s2,s3
> y-a = s4
> Does it answer your question?
>
> Thanks,
> Indranil
>
>
> On Tue, Feb 15, 2011 at 1:28 AM, Kunal Shah <kunal.shah@ericsson.com>wrote:
>
>>  Hi all,
>>
>> I have a question about IGMPv3 state machine. If a group is in EX(X,Y) and
>> a TO_IN(A) is received, the new state according to the RFC is EX (X+A, Y-A).
>> I think this mean remove all the elements of A from Y and add all elements
>> of A to X. This also implies that sources not removed from Y will still end
>> up being added to X. My question is why cant we add only those elemets of A
>> to X which are removed from Y as opposed to adding all the elements of A to
>> X ??
>>
>> If only the elements that are removed from Y are added to X, the new state
>> would look like EX (X+(Y*A), Y-A).
>>
>> Am I missing something here??
>>
>> Kunal
>>
>>
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>