Re: [netmod] default namespace in XPath

[Ladislav Lhotka <[e-mail]>]

On Wed, 2018-03-07 at 14:06 +0100, Martin Bjorklund wrote:
> Ladislav Lhotka <[e-mail]> wrote:
> > Hi,
> > 
> > sec. 6.4.1 in RFC 7950 says in the second bullet item:
> > 
> >     Names without a namespace prefix belong to the same namespace as
> >     the identifier of the current node.
> > 
> > It is unclear what "current node" means:
> > 
> > 1. Is it the context node of the XPath expression, or
> > 
> > 2. is it the schema node corresponding to the parent statement of the
> must/when
> > statement?
> > 
> > For example:
> > 
> > module example-4-a {
> >   ...
> >   container bag {
> >     ...
> >   }
> > }
> > 
> > module example-4-b {
> >   ...
> >   import example-4-a {
> >     prefix "ex4a";
> >   }
> > 
> >   augment "/ex4a:bag" {
> >     when "/quux = 0";
> >     ...
> >     }
> >   }
> >   ...
> > }
> > 
> > What is the namespace of "quux" in the when expression? Is it "example-4-a"
> > (option 1 above) or "example-4-b" (option 2)?
> 
> Just like with all other unprefixed items (except in a
> grouping/typedef), it is supposed to default to the prefix of the
> module where it is defined (lexical scope).  So it is supposed to be
> "example-4-b".  I agree that the term "current node" is misleading.

But then you cannot refer to XPath 2.0 as being the model for this default
namespace concept because in-scope namespaces defined in XPath 2.0 are bound to
element (XPath) nodes.

Lada 

> 
> 
> 
> 
> /martin
-- 
Ladislav Lhotka
Head, CZ.NIC Labs
PGP Key ID: 0xB8F92B08A9F76C67