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Subject: Re: [quicwg/base-drafts] active_connection_id_limit interacts poorly
 with Retire Prior To (#3193)
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There definitely was a reason we avoided making this a strict requirement=
, and I think this played into it, but this is the benefit of having RPT =
delivered in the same frame that delivers a new one. =0D
=0D
Perhaps modify the text to indicate that the error is if the limit is exc=
eeded after retiring any in RPT?=0D
=0D
Or even some non-normative text along the lines of =E2=80=9CIf RPT retire=
s all outstanding CIDS, immediately start sending new packets with the ne=
w CID and make sure you only check the limit after retiring any indicated=
 in RPT=E2=80=9D? =0D
=0D
On one hand, it=E2=80=99s kind of an annoying thing to keep track of. But=
 on the other, making it a hard requirement does decently simplify a lot =
of other scenarios. =0D
=0D
That said, we should probably go dig up the other reasons we avoided this=
 the first time around. =0D
=0D
-- =0D
You are receiving this because you are subscribed to this thread.=0D
Reply to this email directly or view it on GitHub:=0D
https://github.com/quicwg/base-drafts/issues/3193#issuecomment-551254796=

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<p>There definitely was a reason we avoided making this a strict requirem=
ent, and I think this played into it, but this is the benefit of having R=
PT delivered in the same frame that delivers a new one.</p>=0D
<p>Perhaps modify the text to indicate that the error is if the limit is =
exceeded after retiring any in RPT?</p>=0D
<p>Or even some non-normative text along the lines of =E2=80=9CIf RPT ret=
ires all outstanding CIDS, immediately start sending new packets with the=
 new CID and make sure you only check the limit after retiring any indica=
ted in RPT=E2=80=9D?</p>=0D
<p>On one hand, it=E2=80=99s kind of an annoying thing to keep track of. =
But on the other, making it a hard requirement does decently simplify a l=
ot of other scenarios.</p>=0D
<p>That said, we should probably go dig up the other reasons we avoided t=
his the first time around.</p>=0D
=0D
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