Re: [Rfc-markdown] [xml2rfc] New xml2rfc release: v2.25.0

Robert Sparks <rjsparks@nostrum.com> Thu, 29 August 2019 19:35 UTC

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To: Robert Moskowitz <rgm@htt-consult.com>, Henrik Levkowetz <henrik@levkowetz.com>, xml2rfc-dev@ietf.org, xml2rfc@ietf.org
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From: Robert Sparks <rjsparks@nostrum.com>
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Subject: Re: [Rfc-markdown] [xml2rfc] New xml2rfc release: v2.25.0
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Hi Bob -

The message is coming out of pip, and I suspect your default python is 
currently 2.7.

If you run pip --version, it should tell you which version of python 
it's running on (and consequently which version it is installing 
packages for).

There is only one xml2rfc - it can process both v2 and v3 documents. It 
also runs under either python 2 or python 3.

RjS


On 8/29/19 2:22 PM, Robert Moskowitz wrote:
>
>
> On 8/26/19 8:44 AM, Henrik Levkowetz wrote:
>> Hi,
>>
>> This is an automatic notification about a new xml2rfc release,
>> v2.25.0, generated when running the mkrelease script.
>
> Notes on my experience with the upgrade:
>
> I get the standard warning:
>
> DEPRECATION: Python 2.7 will reach the end of its life on January 1st, 
> 2020. Please upgrade your Python as Python 2.7 won't be maintained 
> after that date. A future version of pip will drop support for Python 
> 2.7.
>
> I have both Python2 and 3 installed on my Fedora 30 system.
>
> What is causing this message?  An old version of pip or xml2rfc?
>
> Is there a way to install xml2rfc v3 to start checking it out without 
> loosing v2?
>
> thanks
>
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