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Re: [TLS] DTLS 1.3

"Fossati, Thomas (Nokia - GB)" <thomas.fossati@nokia.com> Fri, 08 July 2016 09:29 UTC

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From: "Fossati, Thomas (Nokia - GB)" <thomas.fossati@nokia.com>
To: Nikos Mavrogiannopoulos <nmav@redhat.com>, "Fossati, Thomas (Nokia - GB)" <thomas.fossati@nokia.com>, Stephen Farrell <stephen.farrell@cs.tcd.ie>
Thread-Topic: [TLS] DTLS 1.3
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Date: Fri, 08 Jul 2016 09:29:42 +0000
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Cc: tls <tls@ietf.org>
Subject: Re: [TLS] DTLS 1.3
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On 08/07/2016 10:05, "Nikos Mavrogiannopoulos" <nmav@redhat.com> wrote:
>On Fri, 2016-07-08 at 08:59 +0000, Fossati, Thomas (Nokia - GB) wrote:
>
>> > How would the hash chain matching work for a server handling
>> > multiple
>> > clients?
>> Sorry, I'm not sure I understand the question.  Are you asking what
>> happens if there is an Id collision between two separate hash chains?
>
>No, my question is much simpler. How would a server handling for
>example 20000 clients, will figure to which chain a hash of H(x)
>belongs to? Will it have to iterate through all the chains (client
>states) and test for matching or there is something more clever than
>that?

Ah! The hash chain would be computed at the end of the handshake, so all L
Ids can be put in a hash table that maps them to the same DTLS context.
When a data record comes in, its Id can be used to look up the context in
O(1).
Clearly the server needs to negotiate a sensible L if it doesn't want to
blow up.

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