Re: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC algorithm
"David McGrew (mcgrew)" <mcgrew@cisco.com> Wed, 20 March 2013 18:18 UTC
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From: "David McGrew (mcgrew)" <mcgrew@cisco.com>
To: "Paterson, Kenny" <Kenny.Paterson@rhul.ac.uk>, "Manger, James H" <James.H.Manger@team.telstra.com>
Thread-Topic: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC algorithm
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Date: Wed, 20 Mar 2013 18:18:08 +0000
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Subject: Re: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC algorithm
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Hi James and Kenny, On 3/20/13 8:36 AM, "Paterson, Kenny" <Kenny.Paterson@rhul.ac.uk> wrote: >Hi James, > >Good questions. My personal view in-line. I'll be interested in hearing >David's viewpoint. > >On 20 Mar 2013, at 05:57, Manger, James H wrote: > >> If you pass additional data (AAD), but no plaintext, to the GCM AEAD >>algorithm you effectively get a MAC algorithm. It even has a name: GMAC. > >Indeed, and it's even standardised in various places :-) > >> >> Presumably it is equally trivial to create a MAC algorithm from any >>AEAD algorithm. Agreed. >> >> You can do this with the AEAD_AES_x_CBC_HMAC_SHA_y algorithms in >>draft-mcgrew-aead-aes-cbc-hmac-sha2-01. However, the output is a 16-byte >>IV, 16-byte ciphertext (encrypting a block of padding), and the >>truncated HMAC output. This is 32 bytes more than a straight HMAC of the >>AAD. Yes, good observation. >> >> Question 1: Is HMAC over AAD-plus-random-IV better cryptographically >>than HMAC over just the AAD? >> > >No, there's no security advantage (that I know of) to having HMAC over >"AAD plus random IV" compared to HMAC over just the AAD. Agreed. > > >> >> When defining a secure message format a tempting simplification is to >>only define how to use an AEAD algorithm. Then if a particular message >>doesn't need confidentiality just put the content into the AAD field and >>leave the plaintext empty. This approach is less attractive if using an >>AEAD algorithm in "MAC mode" incurs an unnecessary 32-byte overhead over >>a dedicated MAC mode. >> >> Question 2: Should draft-mcgrew-aead-aes-cbc-hmac-sha2 add a special >>case for when the plaintext is empty? >> If the answer to Q1 is "No", the special case might be "when the >>plaintext is empty: set the IV to all zeros; and the output is just the >>truncated hash (C = T), omitting the IV and ciphertext". Alternatively, >>the special case might just involve HMAC, with no AES operations. >> If the answer to Q1 is "Yes", the special case might be "when the >>plaintext is empty: the output is C = IV || T, omitting the encrypted >>padding". > >I see the rationale of reducing overhead. Your proposal would also reduce >the randomness requirements of the scheme for this "MAC only" mode. > >But even so I'd prefer not to go down this route because of the potential >for confusion and mis-impementation. A single, clean design without too >many options feels better in that respect. > >While I don't see any security issues immediately, I'd also be concerned >about having a special case that might somehow interact badly with the >general case. Do you see anything troubling there? I recognize both the motivation for reducing bandwidth and the concern about special cases that might inadvertently cause trouble. If there are implementations that would use AEAD_CBC_HMAC as a MAC, then I think it makes sense to do the bandwidth optimization, *if* we can convince ourselves that there is no potential for badness on the decryption side. It seems as though the change would come in Steps 2 and 4 of Section 2.2 "Decryption", which would change to something like: 2. If C contains exactly T_LEN octets, then S is the zero-length String. Otherwise, ... ... 4. If S is the zero-length string, then P is set to the zero-length string. Otherwise, ... At Step 2 of Section 2.1 "Encryption", we would need to say "If P contains exactly zero octets, then S is the zero-length string; skip to step 5." It looks innocuous, but deserves more analysis I think. My inclination is that we should only add this if there are plans to use the algorithm as a MAC. Are there scenarios in which AEAD_CBC_HMAC would be available, but the underlying HMAC would not? I can see value in minimizing the number of entry points to a crypto implementation, but on the other hand, HMAC is already broadly available. David > >Cheers, > >Kenny >_______________________________________________ >Cfrg mailing list >Cfrg@irtf.org >http://www.irtf.org/mailman/listinfo/cfrg
- [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC algorit… Manger, James H
- Re: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC alg… Paterson, Kenny
- Re: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC alg… David McGrew (mcgrew)
- Re: [Cfrg] AEAD_AES_x_CBC_HMAC_SHA_y as a MAC alg… Manger, James H