Re: [Gen-art] Genart last call review of draft-ietf-nfsv4-rpcrdma-cm-pvt-data-06

Chuck Lever <chuck.lever@oracle.com> Wed, 29 January 2020 15:23 UTC

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From: Chuck Lever <chuck.lever@oracle.com>
In-Reply-To: <CAMRcRGR2XkudwuWczgHbF23=E6tAgrzMrUNDNTjJbVR=bmhung@mail.gmail.com>
Date: Wed, 29 Jan 2020 10:23:43 -0500
Cc: gen-art@ietf.org, draft-ietf-nfsv4-rpcrdma-cm-pvt-data.all@ietf.org, nfsv4@ietf.org, last-call@ietf.org
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To: Suhas Nandakumar <suhasietf@gmail.com>
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Subject: Re: [Gen-art] Genart last call review of draft-ietf-nfsv4-rpcrdma-cm-pvt-data-06
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> On Jan 29, 2020, at 12:03 AM, Suhas Nandakumar <suhasietf@gmail.com> wrote:
> 
> Thanks Chuck for the response. Please see inline
> 
>> On Tue, Jan 28, 2020 at 7:52 AM Chuck Lever <chuck.lever@oracle.com> wrote:
>> 
>> Zero is a permitted value for the size fields. Section 5.2 explains how
>> to compute the actual buffer size. If those fields contain zero, the
>> actual send and receive buffer sizes would be 1024 octets.
> 
> 
> [Suhas] I am not sure if i am reading it right here. Section 5.2 would result in the
> value of -1 if the min of the values is Zero (0/1024 - 1). Isn't it so ?

Section 5.2 says:

   Inline threshold sizes from 1KB to 256KB can be represented in the
   Send Size and Receive Size fields.  A sender computes the encoded
   value by dividing the actual value by 1024 and subtracting one from
   the result.  A receiver decodes this value by performing a
   complementary set of operations.

Here, "actual value" means the real size of the buffer. A 1024-octet
buffer would result in (1024 / 1024) - 1 = 0.

The computation done by the receiver is the inverse:

   (0 + 1) * 1024 = 1024

I could replace "actual value" by "buffer size, in octets". Would it
help if the text also spelled out the inverse computation?


--
Chuck Lever