Re: [Roll] MRHOF draft-07 comments

[Federico Consoli <[e-mail]>]

Il 29/03/2012 19.27, Philip Levis ha scritto:
> On Mar 29, 2012, at 1:18 PM, Federico Consoli wrote:
>
>> Il 28/03/2012 11.56, Philip Levis ha scritto:
>>> On Mar 28, 2012, at 12:07 AM, Federico Consoli wrote:
>>>
>>>> Hi, I have a doubt about the root's rank with ETX.
>>>> Assume I have 2 nodes A and B and I use ETX as metric with MRHOF:
>>>> A is root
>>>> B is non-root
>>>> Link between A and B has a cost of 256 (ETX=2)
>>>>
>>>> A got rank of 256(2*,4*) and will annunce a path_cost of 0(1*,3*) in its DIO message in its advertised Rank value(6*).
>>>>
>>>> B will receive a DIO with rank value = 0 so B will set his rank to 256(7*) and will annunce a path_cost of 256.
>>>>
>>>> But now I got 2 nodes with the same rank value. I think it's not a problem with the algorith of DODAG creation but it's not RPL complaint(5*).
>>> Good catch.
>>>
>>> I think the issue here is the MRHOF draft is not clear: A (a root) should advertise a Rank of 256, and B, following 3.3, would advertise a Rank of 256 + MinHopRankIncrease (case 3 of 3.3).
>>>
>>> This does get at a more fundamental issue, one where the rules on Rank and the rules on metrics can diverge. I'd argue that the text saying Root nodes set to MIN_PATH_COST should instead relate to MinHopRankIncrease; 3.3 was designed given the RPL specification, but I think the cur_min_path_cost clause is out of sync with it. What do you think?
>>>
>>> Phil
>> Hi, thank you for your reply.
>>
>> I think that if the root node advertise a Rank of 256 it means that it got a path_cost to the worst parent of 256 (1*), so it means that it got a ETX of 2 to the worst parent.
>> It's not RPL complaint(2*).
>> If instead we suppose that root send packet to itself, it means that the root can lost packet (ETX=2) to itself.
>> IMHO, a way to fix that (still assuming that root send packet to itself) is that root could advertise a Rank of 128 (ETX=1) so it got no loss to itself.
>> Anyway I don't like this fix.
>>
>> I think that a goot fix is that a root set it's rank to MinHopRankIncrease and (only root) MUST use the metric container to carry ETX=0.
>>
>> I think it's a pretty significant change in MRHOF but I have other ideas. What do you think?
>>
>>
>>
>>
>> (1*) MRHOF - Section 3.4
>> "...It then calculates the metric it will advertise in
>> its metric container. This value is the path cost of the member of
>> the parent set with the highest path cost..."
>>
>> (2*) RPL-RFC - Section 8.2.1 - Rules 2
>> "A DODAG root MUST have a DODAG parent set of size zero"
>>
> The RPL specification is what says the Rank value a root must advertise.
>
> 8.2.2.2 says
>     2.  A DODAG root MUST advertise a rank of ROOT_RANK.
Yes. I agree with that. Root nodes got rank=256.
>
> To some degree, absolute ETX values do not matter -- what matters is their relative values. If all DODAG Roots advertise a Rank of 256, corresponding to an ETX of 2, then that's what they advertise, and a route with an computed ETX of 5 involves 3 transmissions within the LLN.
>
> I don't think I'm understanding the issue -- could you explain it again?
>
> Phil
I don't agree that root nodes could advertise a ETX=2.

"Once the preferred parent is selected, the node sets its 
cur_min_path_cost variable to the path cost corresponding to its 
preferred parent. It then calculates the metric it will advertise in its 
metric container. This value is the path cost of the member of the 
parent set with the highest path cost."

Root nodes have parent set of size zero so they got a 
cur_min_path_cost=0 so ETX=0.

Because "a node MUST advertise an approximation of its ETX in its 
advertised Rank value" root nodes must advertise ETX=0.
I agree with the fact that absolute ETX do not matter but I think that 
the root advertisement does not match the definition in the MRHOF draft.


-- 
Regards
Consoli Federico