re: even if the host is "dual-stacked"......
Bob Gilligan <Bob.Gilligan@eng.sun.com> Fri, 17 December 1993 22:17 UTC
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From: Bob Gilligan <Bob.Gilligan@eng.sun.com>
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To: sipp@sunroof.eng.sun.com
Subject: re: even if the host is "dual-stacked"......
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I'm not sure that I understand the various definitions for "dual-stack" that are being tossed about, but Mike O'Dell raised an an important point about how the application layer interface is affected by a new IP layer: > Date: Mon, 13 Dec 93 17:41:12 -0500 > From: mo@uunet.uu.net (Mike O'Dell) > Subject: even if the host is "dual-stacked"...... > > think about the incredible user support problem this creates: > > "No, you gotta use <sip-telnet> to get to host FOO but ip4-telnet > to get to host BAR." In our implementation of SIPP/IPAE, knowledge about which IP packet format (SIPP or IPv4) is being used resides only at the transport layer and below; it does not extend up to the application layer. There is a single, new, API to SIPP and applications that use that API are "C-bit ignorant". Applications treat SIPP addresses as totally opaque buffers; They don't look at the C-bit. TCP, UDP and IP do look at the C-bit of addresses passed in by applications to determine what form of packet (IPv4 or SIPP) to transmit. But applications are not aware of this. An application that opens a TCP connection should never know whether that TCP traffic is being carried by IPv4 or SIPP. To give a concrete example, I used the "telnet" program on one of our SIPP/IPAE test machines that is connected to the Internet to open a couple of TCP connections. This program has been modified to use the new SIPP API. I first opened a TCP connection to a SIPP address that has the C-bit set to 1, and then opened one to a SIPP address that has the C-bit set to 0. The first connection used TCP over IPv4. The second connection used TCP over SIPP. The telnet program did no interpretation at all of the addresses I typed in. IP decided what IP packet format to use (IPv4 or SIPP) based on the address that the telnet program passed in. To see the difference, I used the "snoop" program to capture and display the packets. Here is a script of the first connection run on "ipae-sun", a SIPP/IPAE machine. The destination address, "8404:1:198.41.0.5", is the SIPP address of an IPv4 host. It has the C-bit == 1, and the low-order 32 bits are the IPv4 address of the host: ipae-sun% telnet 8404:1:198.41.0.5 Trying 8404:1:198.41.0.5 ... Connected to 8404:1:198.41.0.5. Escape character is '^]'. SunOS UNIX (rs) (ttypb) *************************************************************************** * -- InterNIC Registration Services Center -- * * For gopher, type: GOPHER <return> * For wais, type: WAIS <search string> <return> * For the *original* whois type: WHOIS [search string] <return> * For the X.500 whois DUA, type: X500WHOIS <return> * For registration status: STATUS <ticket number> <return> * * For user assistance call (800) 444-4345 | (619) 455-4600 or (703) 742-4777 * Please report system problems to ACTION@rs.internic.net **************************************************************************** Please be advised that the InterNIC Registration host contains INTERNET Domains, IP Network Numbers, ASNs, and Points of Contacts ONLY. Please refer to rfc1400.txt for details (available via anonymous ftp at either nic.ddn.mil [/rfc/rfc1400.txt] or ftp.rs.internic.net [/policy/rfc1400.txt]). [sun] InterNIC > telnet> cl Connection closed. And here are some of the packets from the first connection. Note that in this connection, TCP is running over IPv4 (IP in the snoop output): 7 18:54:31.52825 ipae-sun -> 198.41.0.5 ETHER Type=0800 (IP), size = 58 bytes 7 18:54:31.52825 ipae-sun -> 198.41.0.5 IP D=198.41.0.5 S=192.9.5.2 LEN=44, ID=8145 7 18:54:31.52825 ipae-sun -> 198.41.0.5 TCP D=23 S=32794 Syn Seq=1904927232 Len=0 Win=8616 7 18:54:31.52825 ipae-sun -> 198.41.0.5 TELNET C port=32794 ________________________________ 8 18:54:31.61966 198.41.0.5 -> ipae-sun ETHER Type=0800 (IP), size = 60 bytes 8 18:54:31.61966 198.41.0.5 -> ipae-sun IP D=192.9.5.2 S=198.41.0.5 LEN=40, ID=15032 8 18:54:31.61966 198.41.0.5 -> ipae-sun TCP D=32794 S=23 Syn Ack=1904927233 Seq=1186176000 Len=0 Win=4096 8 18:54:31.61966 198.41.0.5 -> ipae-sun TELNET R port=32794 ________________________________ 9 18:54:31.66038 ipae-sun -> 198.41.0.5 ETHER Type=0800 (IP), size = 54 bytes 9 18:54:31.66038 ipae-sun -> 198.41.0.5 IP D=198.41.0.5 S=192.9.5.2 LEN=40, ID=8146 9 18:54:31.66038 ipae-sun -> 198.41.0.5 TCP D=23 S=32794 Ack=1186176001 Seq=1904927233 Len=0 Win=9112 9 18:54:31.66038 ipae-sun -> 198.41.0.5 TELNET C port=32794 ________________________________ 10 18:54:31.68888 ipae-sun -> 198.41.0.5 ETHER Type=0800 (IP), size = 60 bytes 10 18:54:31.68888 ipae-sun -> 198.41.0.5 IP D=198.41.0.5 S=192.9.5.2 LEN=46, ID=8147 10 18:54:31.68888 ipae-sun -> 198.41.0.5 TCP D=23 S=32794 Ack=1186176001 Seq=1904927233 Len=6 Win=9112 10 18:54:31.68888 ipae-sun -> 198.41.0.5 TELNET C port=32794 Here is the script of the second connection. In this one, the destination address, "1404:1:192.9.5.3" is the SIPP address of another SIPP/IPAE host that is located on the same subnet as "ipae-sun". Note that the C-bit of this address is 0: ipae-sun% telnet 1404:1:192.9.5.3 Trying 1404:1:192.9.5.3 ... Connected to 1404:1:192.9.5.3. Escape character is '^]'. UNIX(r) System V Release 4.0 (vanilla) login: telnet> cl Connection closed. And here are some of the packets from the second connection. Note that in this connection, since the two hosts are on the same subnet, TCP is running directly over SIPP (snoop says "SIP"): 46 18:54:59.18772 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 ETHER Type=0800 (IP), size = 62 bytes 46 18:54:59.18772 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 SIP D=1404:1:192.9.5.3 S=1404:1:192.9.5.2 LEN=24, PT=6 46 18:54:59.18772 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TCP D=23 S=32795 Syn Seq=1908575232 Len=0 Win=8616 46 18:54:59.18772 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TELNET C port=32795 ________________________________ 47 18:54:59.19263 1404:1:192.9.5.3 -> 1404:1:192.9.5.2 ETHER Type=0800 (IP), size = 62 bytes 47 18:54:59.19263 1404:1:192.9.5.3 -> 1404:1:192.9.5.2 SIP D=1404:1:192.9.5.2 S=1404:1:192.9.5.3 LEN=24, PT=6 47 18:54:59.19263 1404:1:192.9.5.3 -> 1404:1:192.9.5.2 TCP D=32795 S=23 Syn Ack=1908575233 Seq=1398239232 Len=0 Win=8616 47 18:54:59.19263 1404:1:192.9.5.3 -> 1404:1:192.9.5.2 TELNET R port=32795 ________________________________ 48 18:54:59.24040 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 ETHER Type=0800 (IP), size = 58 bytes 48 18:54:59.24040 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 SIP D=1404:1:192.9.5.3 S=1404:1:192.9.5.2 LEN=20, PT=6 48 18:54:59.24040 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TCP D=23 S=32795 Ack=1398239233 Seq=1908575233 Len=0 Win=8616 48 18:54:59.24040 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TELNET C port=32795 ________________________________ 49 18:54:59.26112 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 ETHER Type=0800 (IP), size = 64 bytes 49 18:54:59.26112 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 SIP D=1404:1:192.9.5.3 S=1404:1:192.9.5.2 LEN=26, PT=6 49 18:54:59.26112 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TCP D=23 S=32795 Ack=1398239233 Seq=1908575233 Len=6 Win=8616 49 18:54:59.26112 1404:1:192.9.5.2 -> 1404:1:192.9.5.3 TELNET C port=32795 I think that the property that applications are "insulated" from knowledge about which IP version is being used is an important feature of IPAE. It simplifies the transition for the users as well as the application programmers.
- even if the host is "dual-stacked"...... Mike O'Dell
- even if the host is "dual-stacked"...... wollman
- Re: even if the host is "dual-stacked"...... bound
- re: even if the host is "dual-stacked"...... Bob Gilligan
- re: even if the host is "dual-stacked"...... minshall
- Re: even if the host is "dual-stacked"...... bound