Re: Is 1111 1110 10 equal to 0xfe80 or 0x3fa?

[Alexandre Petrescu <[e-mail]>]

Le 06/06/2019 à 23:41, Fred Baker a écrit :
> 
> 
>> On Jun 6, 2019, at 10:18 AM, Alexandre Petrescu
>> <[e-mail]> wrote:
>> 
>> I maintain that 1111 1110 10 equals 0x3fa, because that's what my
>> Windows Calculator says: I type 1111 1110 10 and it converts to
>> 0x3fa.
> 
> You're correct if those are the only bits. However, in 1111 1110 10
> you have to also include 00 0000, because it's a /10 prefix. It's
> fe80::/10, not ten bits of information with the least significant bit
> in the "ones" location. 

Sorry, I think there is an error in the Windwos Calculator.
When typing 10 bits in binary it automatically precedes them with two 0 
bits; presumably it is because it wants to have nibbles (groups of 4 
bits) such that to be able to convert in hex.  That makes it display 
0011 1111 1010 even though it is not that what I typed.  And so it 
converts it wrongly into 3fa.

On another hand, the binary value 1111 1110 10 converts into FE8 only if 
I add two 0 bits at the end (not before), like this: 1111 1110 1000. 
But I do not want to add two 0s at the end, because there are only 10 
bits in the LL prefix, not 12.

So I dont know how to write 1111 1110 10 in hexa.  I will look further.

Sorry if this is all known... I will reduce traffic now.

Alex



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