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Re: [MBONED] draft-zhou-mboned-multrans-path-optimization

"Zhouqian (Cathy)" <cathy.zhou@huawei.com> Fri, 23 March 2012 02:32 UTC

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From: "Zhouqian (Cathy)" <cathy.zhou@huawei.com>
To: "Lee, Yiu" <Yiu_Lee@Cable.Comcast.com>, Stig Venaas <stig@venaas.com>
Thread-Topic: [MBONED] draft-zhou-mboned-multrans-path-optimization
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Date: Fri, 23 Mar 2012 02:31:25 +0000
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Cc: "mboned@ietf.org" <mboned@ietf.org>, Ronald Bonica <rbonica@juniper.net>
Subject: Re: [MBONED] draft-zhou-mboned-multrans-path-optimization
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Hi Yiu,
This solution is not only for transition, it also covers the pure v6 case.
About the content stream, there will be only one stream received by MTR because MTR makes comparison.
If the path metric of v4 source> path metric of v6 source, the MTR will choose the path of v6 source. Otherwise, it will choose v4 source. 
If the v4 metric=v6 metric, it will choose one of them.

Best Regards,
Cathy ZHOU


-----Original Message-----
From: Lee, Yiu [mailto:Yiu_Lee@Cable.Comcast.com] 
Sent: Friday, March 23, 2012 10:07 AM
To: Zhouqian (Cathy); Stig Venaas
Cc: mboned@ietf.org; Ronald Bonica
Subject: Re: [MBONED] draft-zhou-mboned-multrans-path-optimization

Hi Cathy,

I am a little confused. Since MTR is for transitioning, why will it
connect to the S6 in the first place? Besides, say you have two types of
receivers (v4 and v6) connected to the v6-only network. At any given time,
there are v4 and v6 receivers watching TV. In this setup, you will have to
stream the content twice anyway because the group address will be
different for native-v6 (v6 source) and v4-embedded v6 (v4 source). Did I
get this wrong?

Thanks,
Yiu


On 3/22/12 9:50 PM, "Zhouqian (Cathy)" <cathy.zhou@huawei.com> wrote:

>There are two cases in Figure 1. One is v6 network connecting to both v4
>and v6 sources via MTR, which is in higher priority and is the main case
>of this document.

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