Re: [MBONED] draft-zhou-mboned-multrans-path-optimization

["Zhouqian (Cathy)" <[e-mail]>]

Sorry, I mean the v4 and v6 interface, rather than the source in my last email. 
Yes, there will be two streams coming from the source. When the two streams coming from v4 and v6 interface separately, MTR will determine whether the two addresses (v4 and v6) have the address format based on draft-ietf-mboned-64-multicast-address-format. If the v6 address is v4-embedded v6 address according to the draft, it means the two streams are the same. If it is not, the two steams are different.
Then the two streams will come to different receivers. 


Best Regards,
Cathy ZHOU


-----Original Message-----
From: Lee, Yiu [mailto:[e-mail]] 
Sent: Friday, March 23, 2012 10:42 AM
To: Zhouqian (Cathy); Stig Venaas
Cc: [e-mail]; Ronald Bonica
Subject: Re: [MBONED] draft-zhou-mboned-multrans-path-optimization

You can't do that right? If I have a v4 receiver connected to the v6-only
network, the v4 receiver has to receive stream from the S4 source. Or you
suggest the access network will statefully convert the v6 group address to
v4 group address?
 

On 3/22/12 10:31 PM, "Zhouqian (Cathy)" <[e-mail]> wrote:

>Hi Yiu,
>This solution is not only for transition, it also covers the pure v6 case.
>About the content stream, there will be only one stream received by MTR
>because MTR makes comparison.
>If the path metric of v4 source> path metric of v6 source, the MTR will
>choose the path of v6 source. Otherwise, it will choose v4 source.
>If the v4 metric=v6 metric, it will choose one of them.
>
>Best Regards,
>Cathy ZHOU
>
>
>-----Original Message-----
>From: Lee, Yiu [mailto:[e-mail]]
>Sent: Friday, March 23, 2012 10:07 AM
>To: Zhouqian (Cathy); Stig Venaas
>Cc: [e-mail]; Ronald Bonica
>Subject: Re: [MBONED] draft-zhou-mboned-multrans-path-optimization
>
>Hi Cathy,
>
>I am a little confused. Since MTR is for transitioning, why will it
>connect to the S6 in the first place? Besides, say you have two types of
>receivers (v4 and v6) connected to the v6-only network. At any given time,
>there are v4 and v6 receivers watching TV. In this setup, you will have to
>stream the content twice anyway because the group address will be
>different for native-v6 (v6 source) and v4-embedded v6 (v4 source). Did I
>get this wrong?
>
>Thanks,
>Yiu
>
>
>On 3/22/12 9:50 PM, "Zhouqian (Cathy)" <[e-mail]> wrote:
>
>>There are two cases in Figure 1. One is v6 network connecting to both v4
>>and v6 sources via MTR, which is in higher priority and is the main case
>>of this document.