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Re: [Tools-discuss] Standalone iddiff?

Jennifer Richards <jennifer@staff.ietf.org> Tue, 05 March 2024 11:30 UTC

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From: Jennifer Richards <jennifer@staff.ietf.org>
Date: Tue, 05 Mar 2024 07:30:16 -0400
Message-ID: <CAFwTvRamOgU+ye5+Bj9y51E-9V3n0A6V2JAi_jA55y5FkA9ngw@mail.gmail.com>
To: Chris Morrow <morrowc=40ops-netman.net@dmarc.ietf.org>
Cc: Kesara Rathnayake <kesara@staff.ietf.org>, Paul Hoffman <phoffman@proper.com>, Tools Team Discussion <tools-discuss@ietf.org>
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Subject: Re: [Tools-discuss] Standalone iddiff?
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Hi Chris,

The termination is guaranteed because it only calls itself a second time if
diff_tool != 'rfcdiff', and then makes that call with diff_tool ==
'rfcdiff'. It won't call itself again.

Jennifer



On Mon, Mar 4, 2024, 11:47 PM Chris Morrow <morrowc=
40ops-netman.net@dmarc.ietf.org> wrote:

>
> Sure, the setup here is:
>   "Start doing diff things, if that times out try myself again with
> (possibly) rfcdiff instead"
>
> then just keep on looping like that recursing 'forever' if the rfcdiff
> tool happens to also choke
> on the input.
>
> With no protection against that (which really is just a counter to the
> function signature and a check
> against max recursion) you're sort of just betting that you never have a
> bad day with rfcdiff.
>
>

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