Re: Planned experiment: A new mailing list for last-call discussions

Barry Leiba <barryleiba@computer.org> Sat, 14 September 2019 22:08 UTC

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From: Barry Leiba <barryleiba@computer.org>
Date: Sat, 14 Sep 2019 18:07:54 -0400
Message-ID: <CALaySJ+-9QpyzinqzYnaeji9Eui0o9U-QXVgYA5+QryrYs9ypg@mail.gmail.com>
Subject: Re: Planned experiment: A new mailing list for last-call discussions
To: Brian E Carpenter <brian.e.carpenter@gmail.com>
Cc: John C Klensin <john-ietf@jck.com>, IETF <ietf@ietf.org>
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> > I have had the impression that, despite dropouts due to volume
> > on the list and other factors, the vast majority of active IETF
> > participants (those who were contributing to focused technical
> > mailings lists such as WG ones and/or coming to meetings and
> > participating in technical work) were still on the IETF list.
>
> I wonder if we could change from an impression to some data?
>
> For example:
>
> (A) How many people* are subscribed to ietf@ ?

About 1800.

But as I scan through the list, I see addresses that I know not to be
active any more.  And it's pretty much impossible to have any idea of
who actually looks at the messages, and so on.

> (B) How many people are eligible under the current NomCom rule?
>
> (C) How many people are "active" in some other sense (e.g. have sent mail to *any* IETF list in the past year)?
>
> How many people are in (A) only, in (A) & (B), in (A) & (C), in (B) or (C) but not (A)?

This all might be interesting, but I think the real data that we'll be
able to collect as we experiment, and that we'll find useful, is this:

(α) How many people unsubscribe from the IETF Discussion list after
the Last Call list is active?

(β) How many people unsubscribe from the Last Call list?

(γ) How many new subscribers do we get for the two lists over time,
and how do they coordinate?

You think?

-- Barry

> We coud add
>
> (D) How many people are subscribed to ietf-announce@
>
> * people = distinct email addresses excluding the + construct.
>
> These data exist if someone in the Secretariat could extract them.
>
> Regards
>     Brian